| Lee Township, Ohio | |
|---|---|
| — Township — | |
| Municipalities and townships of Athens County. | |
| Coordinates: | |
| Country | United States |
| State | Ohio |
| County | Athens |
| Area | |
| • Total | 25.3 sq mi (65.6 km2) |
| • Land | 25.0 sq mi (64.9 km2) |
| • Water | 0.3 sq mi (0.7 km2) |
| Elevation[1] | 781 ft (238 m) |
| Population (2000) | |
| • Total | 2,531 |
| • Density | 101.0/sq mi (39.0/km2) |
| Time zone | Eastern (EST) (UTC-5) |
| • Summer (DST) | EDT (UTC-4) |
| FIPS code | 39-42420[2] |
| GNIS feature ID | 1085755[1] |
Lee Township is one of the fourteen townships of Athens County, Ohio, United States. The 2000 census found 2,531 people in the township, 1,747 of whom lived in the unincorporated portions of the township.[3]
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Located in the southwestern corner of the county, it borders the following townships:
Most of the village of Albany is located in southeastern Lee Township.
Statewide, other Lee Townships are located in Carroll and Monroe Counties.
The township is governed by a three-member board of trustees, who are elected in November of odd-numbered years to a four-year term beginning on the following January 1. Two are elected in the year after the presidential election and one is elected in the year before it. There is also an elected township fiscal officer,[4] who serves a four-year term beginning on April 1 of the year after the election, which is held in November of the year before the presidential election. Vacancies in the fiscal officership or on the board of trustees are filled by the remaining trustees.
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